Question

11. Obtain the Boolean expression for the logic circuit shown below:
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Answer 1

Explanation:

step 1: as we know that output of AND gate is A+B,

            so output of NAND gate will be (A+B)'.

step 2: as we know that output of OR gate is A.B,

            so output of NOR gate will be (A.B)'.

step 3: so as per this diagram output of above NAND gate is ( xⁿ.y)'

            and output of lower NAND gate is (x.yⁿ)'

step 4: output of NOR gate will be (( xⁿ.y)' + (x.yⁿ)')'

step 5: now as per DeMorgan's law: (A+B)' = A'.B'

           so (( xⁿ.y)' + (x.yⁿ)')' = ( xⁿ.y)''. (x.yⁿ)''

                                             = (xⁿ.y). (x.yⁿ)    ( as we know that A'' = A)

so final answer is = (xⁿ.y). (x.yⁿ)

Answer 2

Answer:

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