Question

11
origin
(c) Find the perimeter of a triangle with vertices
0, 4), (0, 0) and (3, 0).​

Answer 1

( 1.5,2)

hope it helps you ✌️ friend

Answer 2

Given :-

Vertices of triangle are (0 ,4) , (0, 0) , (3, 0)

To find :-

Perimeter of a triangle

Solution :-

Refer the attachment

As we know that perimeter of a triangle is nothing but Sum of its sides

Since,

Perimeter = AB+BC+AC

• AB = Distance between A and B
• BC = Distance between B and C
• AC = Distance between A and C

We can find their distances by using distance formula

$= \sqrt{(x_1-x_2)^2+(y_1-y_2)^2}$

Distance between AB =

A = (0,4) B= (0, 0 )

$AB = \sqrt{(0-0)^2+(4-0)^2}$

$AB =\sqrt{0+(4)^2}$

$AB =\sqrt{(4)^2}$

$AB = 4$

Distance between BC =

B =( 0,0) C=( 3, 0)

$BC = \sqrt{(0-3)^2+(0-0)^2}$

$BC = \sqrt{(-3)^2+0}$

$BC = \sqrt{9 }$

$BC = 3$

Distance between AC =

A= (0,4) C= ( 3,0)

$AC = \sqrt{(0-3)^2+(4-0)^2}$

$AC =\sqrt{(-3)^2+(4)^2}$

$AC=\sqrt{9+16}$

$AC=\sqrt{25}$

$AC = \sqrt{5^2}$

$AC =5$

$Perimeter = AB+BC +AC$

$Perimeter = 4+3+5$

$Perimeter= 12 units$

So, the perimeter of a triangle is 12 units