Question

11. PS is a median of APQR. Show that (PQ+ PR) > 2PS.plzz with diagram. please solve this question it's very important to me also so urgent​

Answer 1

Answer:

Hola ^_^

Here is your answer

In ∆ PQR

1. PQ + QS > PS

【 The sum of any two sides of triangle is greater than the third side】

2. PR + RS > PS

【 The sum of any two sides of triangle is greater than the third side】

3. Therefore adding 1 and 2

PQ+ QS+ PR+ RS >2PS

PQ+ QR+ PR> 2PS

【 as QR = QS + RS】

HENCE PROVED .

Hope it helps you ^_^

Step-by-step explanation:

Answer 2

Answer:

Step-by-step explanation:

. PQ + QS > PS

【 The sum of any two sides of triangle is greater than the third side】

2. PR + RS > PS

【 The sum of any two sides of triangle is greater than the third side】

3. Therefore adding 1 and 2

PQ+ QS+ PR+ RS >2PS

PQ+ QR+ PR> 2PS

【 as QR = QS + RS】

HENCE PROVED .

Refer to the attachment