Question

11. Relation between force, mass and acceleration is given by
A) Newton's first law of motion
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B) Newton's second law of motion
O c) Newton's third law of motion
OD) Newton's gravitational law
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E
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Answer 1

$\sf{\underline{\red{\large{Question:-}}}}$

Relation between force, mass and acceleration is given by:-

$\:\:\:\:$(A)Newton's first law of motion

$\:\:\:\:$(B) Newton's second law of motion

$\:\:\:\:$(C) Newton's third law of motion

$\:\:\:\:$(D) Newton's gravitational law

$\rule{400}{2}$

$\sf{\underline{\red{\large{Answ er:-}}}}$

$\rm{\underline{\green{(B)\: Newton's\:second\:law\:of\:motion}}}$

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Additional Information:-

$\pink{\underline{\sf{Newton's\: second \:law\:of\:motion:-}}}$

$\bf{\red{\underline{\boxed{F\:=\:m\:*\:a}}}}$

$\bf{\red{\underline{Let,}}}$

$\rm{\purple{Acceleration\:be\:a}}$

$\rm{\purple{Force\:be\:F}}$

$\rm{\purple{Initial\: velocity\:be\: u}}$

$\rm{\purple{Final\: velocity\: be\:v}}$

$\rm{\purple{Time\:taken\:be\:t }}$

$\rm{\purple{Mass\:be\:m}}$

Deriving the formula:-

Newton's second law of motion says that the force applied is directly proportional to the rate of change of momentum.

⇻We know that momentum = mass * velocity

⇻Initial momentum = mass * initial velocity = m * u = mu

⇻Final momentum = mass * final velocity = m * v = mv

⇻Change in momentum = Final momentum - Initial momentum = mv - mu

⇻Rate of change of momentum = (Change in momentum)/Time = (mv - mu)/t

$F \alpha \frac{(mv - mu)}{t}$

To make it equal, we have to multiply it with a constant, here k.

$F = k \frac{(mv - mu)}{t}$

When k = 1

$F = \frac{(mv - mu)}{t}$

Take m common

$F = \frac{m(v - u)}{t}$

We know that (v - u)/t = a [acceleration]

$F = ma$

Here we get the relation between force(F), mass(m) and acceleration (a).

Answer 2

Answer:B) Newton's second law of motion