Question

11.Show that, (a-b)(a+b)+(b-c)(b+c)+(c-a)(c+a)=0​

Answer 1

Answer:

$\left(a-b\right)\left(a+b\right)+\left(b-c\right)\left(b+c\right)+\left(c-a\right)\left(c+a\right) = 0\\=a^2-b^2+b^2-c^2+c^2-a^2 = 0\\= 0 = 0$

MARK ME AS BRAINLIEST !!

Answer 2

Step-by-step explanation:

your answer is provided in the pick please see it carefully