Math, asked by gurveen51, 2 months ago

11. Show that the points A (1,2), B (-1,-16) and C (0, - 7) lie on the
graph of the linear equation y=9x -- 7.​

Answers

Answered by sukhbirrahul1111111
2

Answer:

For A(1,2), we have 2=9(1)−7=9−7=2

For B((−1,−16), we have -16=9(−1)−7=−9−7=−16

For C(0,−7), we have - 7=9(0)−7=0−7=−7

We see that the line y=9x−7 is satisfied by the points A(1,2),B(−1,−16) and C(0,−7).

Therefore, A(1,2),B(−1,−16) and C(0,−7)are solutions of the linear equation y=9x−7 and therefore, lie on the graph of the linear equation y=9x−7.

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