Question

11. Solve: 3n + 7 = 25
12. Evaluate: (-31)+((-30) + (-1)]
13. Express 7 rupees 7 paise as rupees using decimals.
14. Find the value of 0.5 + 1000
15. A school team won 6 games this year against 4 games won last year. What is the percent
increase?
16. Find the angle which is equal to its supplement.
17. What is the side included between the angles M and N of AMNP?
19. Find the value of the unknown exterior angle x in the below diagrams:​

Answer 1

Answer:

11). 3n+7=25

3n=25-7

3n =18

n=18/3

n=6

Answer 2

Answer:

11. 3n+7=25

3n=25−7

3n=18

n= 18/3

n=6

12. (−31)+ (-30/-1)

= (−31)+30

=−1

13. 1 rupee = 100 paise

7 rupees 7 paise = 7 rupees + 7/100

= 7.07 rupees

14. 1000.5

15. The increase in the number of wins (or amount of change) =6−4=2

Percentage increase

amount of change x 100

original amount or base

= 2÷4 ×100

=50%

16. Let x be two equal angles of its supplement.

Therefore, x+x=180

o

[Supplementary angles]

⇒2x=180°

⇒x= 180°÷2

=90°

Thus, 90° is equal to its supplement.