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Given :-
- The point P(x, y) is equidistant from the points A(5, 1) and B(-1, 5).
To Prove :-
- 3x = 2y
Solution :-
As P is equidistant from A and B
So,
AP = BP
From distance formula
⇒ √{(x - 5)² + (y - 1)²} = √{(x + 1)² + (y - 5)²}
⇒ (x - 5)² + (y - 1)² = (x + 1)² + (y - 5)² [ by squaring both sides ]
⇒ x² - 10x + 25 + y² - 2y + 1 = x² + 2x + 1 + y² - 10y + 25
⇒ - 10x - 2x = 2x - 10y
⇒ - 12y = - 8y
⇒ 12x = 8y
⇒ 3x = 2y
Hence, proved !
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