Question

11. Sum of the areas of two squares is 468 m². If the difference of their perimeters is 24 m, find the sides of the two squares. So, the g​

Answer 1

Answer:

The sides of the first square and the second square, whose sum of the areas is 468 m2 and the difference of their perimeters is 24m, is 18m and 12m respectively.

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Answer 2

Answer:

The sides of the first square and the second square, whose sum of the areas is 468 m2 and the difference of their perimeters is 24m, is 18m and 12m respectively.