Question

11. Sum of the digits of a two digit number is 11. When we interchange the digits, it is
found that the resulting new number is greater than the original number by 63. Find
the two digit number.
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Answer 1

Answer:

let unit place digit be x

tens place digit be 11-x

original no= x+10(11-x) = x+110-10x=110-9x

after Interchanging digits

new no=10x+11-x=9x+11

according to the question

9x+11 = 110-9x+63

9x+9x=173-11

18x = 162

x=162/18 = 9

original no=110-9*9=110-81 = 29