Question

11
$11 \sqrt{n} = \sqrt{112} + \sqrt{343} \: then \: n \: value$

Answer 1

$\sqrt{n} = ( \sqrt{112} + \sqrt{343} ) \div 11 \\ square \: both \: sides \\ n = {( \sqrt{112} + \sqrt{343)} }^{2} \div 121 \\ n = (112 + 343 + 2 \sqrt{112 \times 343} ) \div 121 \\ n = (455 + 2(196)) \div 121 \\ n = (455 + 392) \div 121 \\ n =8 47 \div 121 \\ n = 7$
here is your complete answer.... mark as brainliest if helped