Physics, asked by pavithrav16122005, 3 months ago

11 th maths வர்க்கமூலம் காண்க
 \sqrt{9801}

Answers

Answered by deepikamr06
0

Answer:

11 th maths வர்க்கமூலம் காண்க

 \sqrt{9801}

Explanation:

 \sqrt{9801 = 99}

Answered by presentmoment
6

\sqrt{9801} = 99

Explanation:

Just we learn only 1 to 10² table value \sqrt{9801} square root.

step 1 :

  • Last itself we have to divide 2 digit

\sqrt{98|01}

  • we take the first term 98,98 is the square value of
  • 9² = 81
  • 10² = 100.
  • Don't take to maximum of the given number.
  • so we obtain 9² table.

step 2:

  • We find the last digit of the sum
  • 1 is the last digit of the sum,

       1  →  1 , 9

  • last digit one value will be applied
  • 1 + 9 = 10

step 3:

  • In First step we find one answer 9
  • In second step we find one answer 10
  • then we multiple the numbers
  • 9 × 10 = 90
  • \sqrt{98|01} ∴ so 90 is the minimum value of 90.
  • 9 ⇒ 1 → max   9 → min

      *     9   1  

                 9         99 is the square root of \sqrt{9801}

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