Math, asked by devyanirox3, 5 months ago

11. The age of a father is seven times his son's age. After 4 years sum of
their ages is 56 years. What is the present age of the son (in years)?
(a) 8
(b) 6
(c) 5
(d) 10​

Answers

Answered by raotripti10gmailcom
0

Answer:

a ) 8 .....,........

Step-by-step explanation:

I think it right..

Answered by Anonymous
21

Let x be the present age of the son.

So father's age will be 56-x

After 4 years the age of the father will be 7 times that of his son

(56 - x + 4) = 7(x + 4)

 =  > (60 - x) = 7x + 28

 =  >8x = 32

 =  > x =  \frac{32}{8}

 =  > x = 4

Similar questions