Question

11)
The angles of a quadrilateral are in A.P.
and the greatest angle is double the
least. Find angles of the quadrilateral in
radian.​

Answer 1

Answer:

let the angles be a-x,a,a+x,a+2x

least angle = a-x

greatest angle = a+2x

2(a-x)=a+2x

2a-2x=a+2x

2a-a=2x+2x

a=4x

angles = 4x-x,4x,4x+x,4x+2x

=3x,4x,5x,6x

the sum of all the angles in a quadrilateral=360 degree = 2pi

3x+4x+5x+6x=360

18x=360

x=360/18=20 degree

angles = 3x=60 degree = pi/3

4x= 80 degree=4pi/9

5x=100 degree = 5pi/9

6x=120 degree= 2pi/3

Step-by-step explanation: