Question

11. The annual rate of growth in population of a town is 10%. If its present population is 3327 what was it 3 years ago?

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Answer 1

Amount (A) = P (1 + R/100)n [Where, A = Amount with compound interest  P = Present value  R = Annual interest rate  n = Time in years]

THE FORMULA

$(population \: = p(1 + \frac{r}{100} )^{2}$

$= 33275 \: = p(1 + \frac{10}{100} )^{3}$

$= 33275 = p(1 + \frac{1}{10} )^{3}$

$= 33275 = p( \frac{11}{10} )^{3}$

$= 33275 = p \times \frac{1331}{1000}$

$= p = 33275 \times \frac{1000}{1331}$

$= p = 25 \times 1000$

$= p = 25000$

3 years ago population is 25000.

Answer 2

Step-by-step explanation:

$\large \color{teal}{ \boxed{ \color{olive}{ \boxed{ \color{cyan}{given}}}}}$

rate of population =10%

present population =3327

$\large \color{peach}{ \boxed{ \color{coral}{ \boxed{ \color{violet}{solving \: the \: question}}}}}$

let the population 3 years ago=x

then ATQ

$\boldsymbol{ \rightarrow}present \: population = x(1 + { \frac{r}{100}})^{n} \\ \boldsymbol{ \rightarrow}x(1 + { \frac{10}{100} })^{3} = 3327 \\ \boldsymbol{ \rightarrow}x \times \frac{110}{100} \times \frac{110}{100} \times \frac{110}{100} = 3327 \\ \boldsymbol{ \rightarrow}x \times 1.331 = 3327 \\\boldsymbol{ \rightarrow} x = \frac{3327000}{1331} \\\boldsymbol{ \rightarrow} x = 2499 \: approx$

2499 (approx) was the population 3 years ago

और क्या तकलीफ है आपको