Question

11. The area of a rectangle gets
reduced by 5 sq. m, if its length is reduced by 2 m and breadth is increased by 3 m. If we increase the length by 3 m and the breadth by 2 m, then the area is increased by 50 sq. m. Then the length and breadth of the rectangle are?​

Answer 1

Then as per first condition ,

(x−5)(y+3)=xy−9

xy−5y+3x−15=xy−9

3x−5y=6       −−−−−(1)

As per second condition, 

(x+3)(y+2)=xy+67

xy+3y+2x+6=xy+67

2x+3y=61     −−−−−(2)

On multiplying equation (1) by 3 and equation (2) by 5 then adding, we get

9x−15y=18

10x+15y=305

−−−−−−−−−−

19x=323

∴x=17

Hence, the length of the rectangle is 17m.

The last are increased is 50 m i have given answer for 67 m so you can change numbers and solve