Math, asked by goudminni, 4 months ago

11. The average of square of first 6 consecutive even numbers is:
O None of these
O 54
O 60
O 60.66

Answers

Answered by ktejasri07

2

Answer:

60.66

Step-by-step explanation:

((2^2)+(4^2)+(6^2)+(8^2)+(10^2)+(12^2))/6

=>60.66

Answered by patilpooja02102005

0

Answer:

60.66

Step-by-step explanation:

n = 6

Average=2(6+1)(2*6+1)/3

=2*7*13/3

=60.66

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