Question

11. The base of a parallelogram is twice its height. If
the area is 392 cm?. Find the base and height:​

Answer 1

Answer:

Base = 14

Height= 28

Step-by-step explanation:

Let height be x

Then height = 2x

Area=392

Area = base×height

Area = 2x × x

392=2x^2

X^2 = 392/2

X^2= 196

X = 14

2x = 28

Height = 28

Base = 14

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Answer 2

Question : The base of a parallelogram is twice its height. If the area is 392 cm^2. Find the base and height.

Solution :

$\underline{\bold{Given:}}$

• $Area \: of \: the \: parallelogram = 392 \: {cm}^{2}$

$\underline{\bold{To\:Find:}}$

• The base and height of the parallelogram.

Let the height be x cm.

Then, its base = 2x cm

$\boxed {\blue{Area \: of \: the \: parallelogram = base\times height}}$

Atq,

$\implies Area \: of \: the \: parallelogram = base \times height \\ \implies 392 = 2x \times x \\ \implies 392 = 2 {x}^{2} \\ \implies \frac{392}{2} = {x}^{2} \\ \implies 196= {x}^{2} \\ \implies \sqrt{196} = x \\ \implies \sqrt{14 \times 14} = x \\ \implies14 = x \\ \implies x= 14$

$\boxed{\green{Base=(2\times 14)\:cm=28\:cm}}$

$\fbox{\green{Height=14 \:cm}}$

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