Question

11. The breadth of a rectangular hall is 20% less than twice of its length .if length of the hall is y m ,then
determine the breadth of the hall?
​

Answer 1

Breadth of hall =$\frac{8y}{5}$

Step-by-step explanation:

Given,Length of hall=y

According to question,

Breadth of hall=$2y-20\% \times 2y$

                     =  $2y-\frac{20\times2y}{100}$

                    =$2y-\frac{2y}{5}$

                    =$\frac{10y-2y}{5}$

Breadth of hall =$\frac{8y}{5}$

Answer 2

Answer:

Given,Length of hall=y

According to question,

Breadth of hall=2y-20% times 2y2y−20%×2y

= 2y-20times2y1002y−

100

20×2y

=2y-\frac{2y}{5}2y−

5

2y

=\frac{10y-2y}{5}

5

10y−2y

Breadth of hall =\frac{8y}{5}

5

8y