Math, asked by chaitrakarri, 7 months ago

11. The diagonals of quadrilateral PQRS
intersect at O, at right angles. Prove that
PQ2 + SR2 = PS2 + QR2.​

Answers

Answered by DarkCreed
2

Answer:

Given that , PQRS is a quadrilateral in which diagonal PR and QS intersect at a O . we know that sum of any two side of a triangle is greater than the third side . Hence Proved.

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