Question

11. The diagonals of quadrilateral PQRS
intersect at O, at right angles. Prove that
PQ2 + SR2 = PS2 + QR2.​

Answer 1

Answer:

Given that , PQRS is a quadrilateral in which diagonal PR and QS intersect at a O . we know that sum of any two side of a triangle is greater than the third side . Hence Proved.