Question

11. The diameters of three circles are in the ratio
3:5:6. If the sum of the circumferences of
these circles be 308 cm; find the difference
between the areas of the largest and the
smallest of these circles.

Answer 1

Answer:

ANSWER

Given,

Diameter of three circle=3:5:6

Sum of the circumference=308cm

Let the diameter of the circles be 3x,5x,6x

Now,

π(3x)+π(5x)+π(6x)=308

=>14xπ=308

=>x=

2×22

308

=>x=7

Therefore,

Diameter of the largest side=6×7

=42

Radius of largest circle=

2

6×7

=21

Diameter of the smallest circle=3x

=3×7

=21

Radius of smallest circle=

2

3×7

=10.5

Difference of areas of largest and smallest of the circles=π(21)

2

−(π(10.5)

2

=1039.5cm

2

Answered By

toppr

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Answer 2

we have to do the sum of the ratio 3:5:6:

so, 3+5+6=14

308÷14=22 so,