11. The diameters of three circles are in the ratio
3:5:6. If the sum of the circumferences of
these circles be 308 cm; find the difference
between the areas of the largest and the
smallest of these circles.
Answers
Answer:
ANSWER
Given,
Diameter of three circle=3:5:6
Sum of the circumference=308cm
Let the diameter of the circles be 3x,5x,6x
Now,
π(3x)+π(5x)+π(6x)=308
=>14xπ=308
=>x=
2×22
308
=>x=7
Therefore,
Diameter of the largest side=6×7
=42
Radius of largest circle=
2
6×7
=21
Diameter of the smallest circle=3x
=3×7
=21
Radius of smallest circle=
2
3×7
=10.5
Difference of areas of largest and smallest of the circles=π(21)
2
−(π(10.5)
2
=1039.5cm
2
Answered By
toppr
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we have to do the sum of the ratio 3:5:6:
so, 3+5+6=14
308÷14=22 so,