Question

11. The difference between two numbers is 26 and one number is three
times the other. Find the numbers
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Answer 1

Let the larger number be x and the smaller number be y. Then, we have: x –y = 26 ………….(i) x = 3y …………(ii) On substituting x = 3y in (i), we get: 3y –y = 26 ⇒ 2y = 26 ⇒ y = 13 On substituting y = 13 in (i), we get: x – 13 = 26 ⇒ x = 26 + 13 = 39 Hence, the required numbers are 39 and 13

Answer 2

↬ Solution :-

Let first number be x

and second number be y

⸕ According to the question,

• x - y = 26 .............................(i)

• x = 3y

• x - 3y = 0 ............................(ii)

⸕ From equation (i),

x - y = 26

➝ x = 26 + y ...............................(iii)

⸕ Putting the value of x in equation (ii)

x - 3y = 0

➝ 26 + y - 3y =0

➝ 26 - 2y = 0

➝ -2y = -26

➝ y = $\rm\:\cancel\dfrac{-26}{-2}$

➝ y = 13

⸕ Putting the value of y in equation (iii),

x = 26 + y

➝ x = 26 + 13

➝ x = 39

Hence,the first number will be 39 and second number will be 13.