Question

11. The displacement of SHM is given by y = 5 cos (10 t +0.6).
What is the initial phase of the SHM?
(a) 5 rad
(b) 10 rad
(c) 0.6 rad
(d) None of these
1:
a to SHM
iron​

Answer 1

Explanation:

initial phase to pi by 2 hi hoga

angular frequency 10 hoga aur wave number0.5 hoga i hope this is sufficient for u

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Answer 2

Answer:

The initial phase of the SHM is 0.6 rad.

(c) is correct option.

Explanation:

Given that,

The displacement of SHM is

$y=5\cos(10t+0.6)$

We need to calculate the initial phase of SHM

Using general equation of SHM

$y = A\cos(\omega t+\phi)$

Where, y = displacement

A = amplitude

t = time

$\phi$ = phase

On comparison of given equation from general equation

The amplitude is

$A =5\ m$

The initial phase is

$\phi=0.6\ rad$

Hence, The initial phase of the SHM is 0.6 rad.