11. The dome of a temple is in the shape of
a cone with radius 3.5m and height 12 m.
Find the cost of painting its outer surface
at the rate of 30/m2.
Answers
Given : The dome of a temple is in the shape of a cone with radius 3.5m
and height 12 m.
Rate of cost of painting Rs 30/m²
To Find : cost of painting its outer surface
Solution:
radius r= 3.5m = 7/2 m
Height h = 12 m
Slant height = L
L² = r² + h²
=> L² = (7/2)² + 12²
=> L² = ( 7² + 24)²/2²
=> L² = 25²/2²
=> L = 25/2 m
outer surface = πrL
= (22/7) (7/2) (25/2)
= 275/2 m²
Rate of cost of painting Rs 30/m²
Hence cost of painting its outer surface = 30 x 275/2
= 4,125 Rs
Learn More:
बवत्तीय बेलन के आधार की त्रिज्या 5 ...
brainly.in/question/13386500
From a solid cylinder of height 24 cm and diameter 10 cm, two ...
brainly.in/question/2705273
The bottom of a right cylindrical shaped vessel made from metallic ...
brainly.in/question/8993181
Step-by-step explanation:
please mark as briliyant