Question

11. The factors of x² + 8x + 16 are
(x + 4)2
O (X - 4)
O (x - 2)2
O (x + 2)2​

Answer 1

Answer:

x-4

Step-by-step explanation:

x²+8x+16=0

By factorisation method

x²+4x+4x+16=0

x(x+4)+4(x+4)=0

(x+4)(x+4)=0

x=-4,x=-4

Answer 2

$\Huge\mathfrak\blue{{\rm{A}}nswe{\rm{R}}}$

${}$

$\bf{{\underline{To~factorise}}:}$

$\rm{~~~~~~~~~~x^{2}+8x+16}$

$\bf{{\underline{Identity}}:~a^{2}+2ab+b^{2}=(a+b)^{2}}$

$\rm\implies{(x)^{2}+2(x)(4)+(4)^{2}}$

$\rm\implies{(x+4)(x+4)}$

$\rm\implies{\blue{\underline{\underline{\bf (x+4)^{2}}}}}$

$\bf\therefore{{\underline{Factors~are}}:}$

• $\rm{\blue{\underline{\boxed{\bf (x+4)^{2}}}}}$