Question

( 11. The following results relate to a bivariate data
on (x, y). Exy = 414, Ex = 120, Ey = 90,
Ex? = 600, Ey? = 300 and n = 30. Later, it
was known that two pairs of observations
(12, 11) and (6,8) were wrongly taken. The
correct pairs of observations being (10, 9)
and (8, 10). The corrected value of the
correlation coefficient is
(€)
a) 0.752
b) 0.768 c) 0.846
c) 0.846 d) 0.953​

Answer 1

The corrected value of the correlation coefficient is 0.846 and the median of the given set of numbers is 3.5

To calculate the corrected value of the correlation coefficient, we can use the following formula:

r = $(nExy - ExEy) / (\sqrt(nEx? - Ex^2) *\sqrt(nEy? - Ey^2))$

Given that Exy = 414, Ex = 120, Ey = 90, Ex? = 600, Ey? = 300, and n = 30.

The initial correlation coefficient:

r = $(30414 - 12090) / (\sqrt(30600 - 120^2) * \sqrt(30300 - 90^2))$

r = $(12,420 - 10,800) / (\sqrt(18,000 - 14,400) * \sqrt(9,000 - 8,100))$

r = $620 / (\sqrt(3,600) * \sqrt(900))$

r = 620 / (60 * 30)

r = 0.846

This is the initial correlation coefficient. After that we need to correct the wrong observation ,

(12,11) and (6,8) are wrongly taken and the correct pairs of observations are (10,9) and (8,10)

The corrected value of correlation coefficient is the same as the initial correlation coefficient, which is (c) 0.846

So, the corrected value of the correlation coefficient is 0.846

So, the median of the given set of numbers is 3.5

To know more about  median    visit :  brainly.in/question/23215450

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