11.
The frictional force of the air on a body of mass Ikg falling with an acceleration of 9 5m per second² is
a/9.8N
b) 9.5 N
c) 0.3 N
a) 9.8 N
Answers
Answered by
1
Answer:
From FBD, ma=mg−f
or f=m(g−a)=0.25(9.8−9.2)
take g=9.8m/s
Answered by
0
Answer:
From free body diagram , ma=w-f , f=m(g-a)=0.25(9.8-9.2)
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