11. The given figure shows a right AABC which is right-angled at B. BD AC and AB = BC = 10 cm. What is the length of AD?
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In △ABD and △ABC we have BD=BC
AB=AB [Common]
∠ABD=∠ABC=90∘
∴ By SAS criterion of congruence we get
△ABD≅△ABC
⇒AD=AC and ∠DAB=∠CAB [By CPCT]
⇒AD=AC and ∠DAB=x [∴∠CAB=x]
Now, ∠DAC=∠DAB+∠CAB=x+x=2x
∴∠DAC=∠ACD
⇒DC=AD [Side Opposite to equal angles]
⇒2BC=AD since DC=2BC
⇒2BC=AC Since AD=AC
Hence proved.
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