Question

11.
The HCF oftwo numbers is 23 and their LCM is 1449. If one of the number is 161. then the
other number is
[ ]
b) 207
c) 1449
d) None
The product of LCM and HCF oftwo number is equal to
( ]
a) 23
12.​

Answer 1

Answer:

Given, HCF=23

LCM=1449

Let the two numbers be a and b. Let a=161. We have to find b.

We know that

HCF(a,b)×LCM(a,b)=a×b

⇒23×1449=161×b

⇒23× (1449/161) =b

⇒b=23×9

∴b=207

Thus, the other number is 207.

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