11. The number of ways of permuting the letters of the word DEVIL so that neither D is
the first letter nor L is the last letter is :
(a) 36
(b) 114
(c) 42
(d) 78
answer is 78 so please explain
Answers
Total arrangement with the letters of the word
DEVIL =5! =120
No. of arrangement starting with D =24=4!
No. of arrangement ending with L =24=4!
No. of arrangement that begin with D and end with L is =6
No. of arrangements required =120−(24+24−6)= 78
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Answer:
The number of ways of permuting the letters of the word DEVIL so that neither D is the first letter nor L is the last letter is 78
Step-by-step explanation:
Total no.of arrangements with the letters of the word DEVIL =5! =120
The number of arrangements starting with D =24=4!
number of arrangements ending with L =24=4!
number of arrangements that begins with D and end with L is =6
number of arrangements required =120−(24+24−6)= 78
The number of ways of permuting the letters of the word DEVIL so that neither D is the first letter nor L is the last letter is 78