Question

11. The perimeter of a rectangle is 60 m and the ratio
between length to the breadth is, 7 : 3. Find the area
of the rectangle-​

Answer 1

$\huge\mathfrak{Answer:-}$

Perimeter of a rectangle = 2(l+b)

= 60 m

Let the length and breadth be 7x and 3x respectively

According to problem,

2(7x + 3x) = 60

or 14x + 6x = 60

or 20x = 60

or x = 60/20

or x = 3

Thus ,

Length - 7(3)

= 21 m

Breadth - 3(3)

= 9m

Area of a rectangle = Length × Breadth

= 21 × 9

= 189 m

Area of the rectangle = 189m

Answer 2

Answer:

The area of the rectangle is 189 metres

Step-by-step explanation:

Let the ratio of the length and breadth be 'X'.

So, the perimeter of the rectangle is:-

2(length + breadth) = 60

2(7X + 3X) = 60

2(10X) = 60

20X = 60

X = 60/20 = 3

So, the length will be 7X = 7 (3) = 21m

and the breadth will be 3X = 3(3) = 9 m

And the area of the rectangle is

Length (Breadth) = 21m (9m)

= 189 m

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