Question

11. The perimeters of two squares are 60 metres and 144 metres respectively. Find the
perimeter of another square equal in area to the sum of the first two squares.
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Answer 1

Given : The perimeters of two squares are 60 metres and 144 metres respectively.

　

To find : What is the perimeter of another square equal in area to the sum of the first two squares.

　

Solution : As per the question we need to know the sum of first two squares, to find the perimeter of square.

　

$:\implies\sf{First \: square = \dfrac{60}{4}}$

　

$:\implies{\sf{\underline{\boxed{\sf{First \: square = 15 \: m}}}}}$

　

　

$:\implies\sf{Second \: square = \dfrac{144}{4}}$

　

$:\implies{\sf{\underline{\boxed{\sf{Second \: square = 36 \: m}}}}}$

　

Finding the sum of first two squares :

$:\implies\sf{Sum = 15^{2} + 36^{2}}$

　

$:\implies\sf{Sum = 225 + 1296}$

　

$:\implies{\sf{\underline{\boxed{\sf{Sum = 1521}}}}}$

　

　

$:\implies\sf{Side = 39^{2} = 1521 \: m}$

　

$:\implies{\sf{\underline{\boxed{\sf{Side = 39 \: m}}}}}$

　

Finding the perimeter of square :

$:\implies\sf{Perimeter = 39 \times 4}$

　

$:\implies{\sf{\underline{\boxed{\sf{156 \: m}}}}}$