Question

11. The population of a town increased by 6% in one year. If the population after the increase is 3,81,600, find the population before the increase.​

Answer 1

Answer:

the answer is 360000

Step-by-step explanation:

please give me brainly

Answer 2

Answer:

3,60,000

Step-by-step explanation:

Let the original population of town be x

Percentage increased= 6%

Population increased= 3,81,600

∴ The equation formed:

   ⇒ x + ( x*6/100) = 3,81,600

   ⇒ x + 6x/100= 3,81,600

   ⇒ 100x + 6x/100= 3,81,600

   ⇒ 106x/100= 3,81,600

   ⇒ 106x= 3,81,600*100

   ⇒ 106x= 3,81,60,000

   ⇒ x= 3,81,600,000/106

   ⇒ x= 3,60,000

Thus the original population was 3,60,000