Question

11. The population of a village was 5,000 in the beginning of the year 2000. The population of the
village was growing at the uniform rate of 10% per annum. In the beginning of the year 2002 there
was an epidemic, as a result of which the population was reduced by 20%. After that the
population was increasing at the rate of 5% per annum. Find the population of the village at the
end of the year 2003.

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Answer 1

Answer:

4,620

Step-by-step explanation:

Population of village in year 2000 = 5,000

Rise of population in year 2001= 10%

Decline of population in year 2002= 20%

Rise of population in year 2003= 5%

Note: Formula for calculating the population at the end of the period=

Initial population × (1 ± rate of increase or decline/100) ×...-for each year

Population the end of 2003= $5000(1+\frac{10}{100} )(1-\frac{20}{100} )(1+\frac{5}{100} )$

                                              = 5000 × $\frac{11}{10}$ × $\frac{4}{5}$ × $\frac{21}{20}$

                                              = 4,620

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