Question

11. The position (x) of a body moving along a straight line at time t is given by
x = (3t2 - 5t + 2)m. Find (i) Velocity at t=2s (ii) Acceleration at t=2s and draw the
corresponding velocity-time (v-t) and acceleration-time (a-t) graphs.​

Answer 1

Given :-

Position of particle = x = (3t² - 5t + 2)m.

Here, we are asked to find Velocity as well as Acceleration of particle at t = 2s.

In this question we will differentiate 'x' w.r.t dt in order to find Velocity and after finding velocity we will again differentiate to find the Acceleration of the particle.

In first case, finding Velocity.

v = dx/dt

v = d(3t² - 5t + 2)/dt

v = 6t - 5

Putting the value t = 2s

v = 6 × 2 - 5

v = 7 m/s.

Again, Differentiating value of v w.r.t dt in order to find Acceleration.

a = dv/dt

a = d(6t - 5)/dt

a = 6 m/s²

Answer 2

Answer:

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