Question

11. The radius of a circle is 17 cm. A chord of length 30 cm is drawn. Find the distance of the chord from the centre.

Answer 1

$\huge{\underbrace{\overbrace{\mathbb{\pink{ꜱᴏʟᴜᴛɪᴏɴ}}}}}$

Given : Radius of circle is 17 cm and Chord Length =30 cm

Point that matter : Distance from Chord to centre.

This means the distance from chord to centre and we know by theorum that line from centre that bisects AB is perpendicular bisector.

To Find: OL

ꜱᴏʟᴜᴛɪᴏɴ:AL = 1/2 AB

AL= 15 cm

In Right, △ BOL,

${ob}^{2} = {ol}^{2} + {bl}^{2}$

${17}^{2} = {ol}^{2} \ + {15}^{2}$

${17}^{2} - {15}^{2} = {ol }^{2}$

√[(17+15) (17-15)] = OL

8 cm = OL

ʜᴇɴᴄᴇ, ʀᴀᴅɪᴜꜱ ᴀɴᴅ ᴄʜᴏʀᴅ ᴀʀᴇ ᴀᴛ ᴛʜᴇ ᴅɪꜱᴛᴀɴᴄᴇ ᴏꜰ 8 ᴄᴍ.