Chemistry, asked by krachna47, 1 month ago

11: The rate constant k of a first order reaction is given by the equation : 2.303 (a) k = (t)log. (A-2) 2.303 (b) k= (a - x) (1) log10 ( 2.303 (c) ka (t) log 10 (n-3) 2.303 (d) k = (t)log 10 ta-x) 17​

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Answered by GraceS
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The rate constant k of a first order reaction is given by the equation : k= (a - x) (1) log10 ( 2.303)

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