Question

11. The ratio of the measures of a side of a triangle is 2:3:5. If the
semiperimeter is 90cm then find the measure of the longest side of the
triangle.​

Answer 1

Answer:

2x + 3x + 5x = 90

10x = 90

x = 90/10

x= 9

then the sides are = 2x = 2*9 = 18

= 3x = 3*9 = 27

= 5x = 5*9 = 45

Now semiperimeter =

sum of sides of triangle/2

= 18+27+45/2

=45

using herons formula

=√s(s-a)(s-b) (s-c)

=√45(45-18)(45-27)(45-45)

= √45(27)(18)(0)

= 0

please mark brainliest it took me so much time

Answer 2

Answer:

$Semi \: \: Perimeter = 90 \: cm \\ Total \: \: Perimeter : \\ 90 \: cm + 90 \: cm \\ = 180 \: cm \\ \\ side \: \: A : 2x \\ side \: \: b : 3x \\ side \: \: c : 5x \\ \\ Measure \: \: of \: \: the \: \: sides \: \: are : \\ 2x + 3x + 5x = 180 \\ 10x = 180 \\ x = \frac{180}{10} \\ x = \underline{ \underline{ 18}} \\ \\ Measures \: \: of \: \: Sides \\ { \large A }: 2x \: \: ➺ \: \: 2(18) \: \: ➺ \: \: 36 \: cm \\ { \large B}: 3x \: \: ➺ \: \: 3(18) \: \: ➺ \: \: 54 \: cm \\ { \large C}: 5x \: \: ➺ \: \: 5(18) \: \: ➺ \: \: 90 \: cm \\ \\Therefore, \: \: Measure \: \: of \: \: the \\ Longest \: \: side \: \: of \: \: Triangle : \\ \large \cal \color{indigo} 90 \: cm$