Question

11. The side of a square tile is 10 cm. How many tiles can be fixed on one side of a wall which is 2.5 m long and 2 m high ? If the tiles are available at * 4 per dozen, find the cost of covering the wall of the room with tiles.

ans ...500
plz ans me detail​

Answer 1

area of 1 tile = 10 x 10=100 cm²

area of floor =2.5 x  2=5 M =50000 cm²

NUMBER OF TILE REQUIRED= AREA OF FLOOR /AREA OF TILE

==> 50000/100

===>500 TILES ARE REQUIRED

COST:-

FOR 1 DOZEN =12 TILES S COST=4

==>12 = 4 RS

500=$\frac{4}{12}$ x 500

500/3

==166.6 RS

HOPE IT HELPS U

Answer 2

$\huge\mathfrak\red{Hello}$

$\huge\mathfrak\red{Question}$

11. The side of a square tile is 10 cm. How many tiles can be fixed on one side of a wall which is 2.5 m long and 2 m high ? If the tiles are available at * 4 per dozen, find the cost of covering the wall of the room with tiles.

$\huge\mathfrak\red{Answer}$

Length of wall = 2.5 m =250 cm{as it's 1 m=100cm}

Height of wall=2m=200cm {as it's 1 m=100cm}

Area of wall = length × breadth

the breadth will be the thickness of wall but we need to calculate the area of wall faces .

So we will take as it's height

So,

Area of wall = length × height

Area=250 ×200 =50000cm²

Therefore ,

side of 1 tile =10 cm

Area of square tiles =side²

= 10² =100cm²

$total \: no. \: of \: tile \\ = \frac{total \: area \: of \: wall}{area \: of \: 1 \: tile}$

No. of tiles

$=\frac{50000 {cm}^{2} }{100 {cm}^{2} }$

so we will cancel out the both and will get 500 tiles

So your answer is 500 tiles.

$\huge\mathfrak\red{hope \: it \: is \: helpful}$

$\huge\mathfrak\red{Jai \: Bholenath}$