Question

11. The side of a square tile is 10 cm. How many tiles can be fixed on one side of a wall which is 2.5 m long and 2 m high? If the tiles are available at 4 per dozen, find the cost of covering the wall of the room with tiles.​

Answer 1

CONSIDER THE TILE

• side = 10 cm

• area = side²

= 10 × 10

= 100cm²

CONSIDER THE WALL

• length = 2.5 m

• breadth = 2m

• Area = Length × breadth

• = 2.5 × 2

• = 5 m²

• = 50000 cm² [ 1m² = 10000 cm² ]

• No. of tiles = area of wall / area of tile

• = 50000 / 100

• = 500

1 dozen = 12 units

no. of dozens of tiles = 500 / 12

cost of tiles = 500 × 4 / 12

= 166.66 Rs

Answer 2

Area of square = side * side

= 10 cm * 10 cm

= 100 cm

Area of wall = length * breadth

= 2 m * 2.5 m

= 5o m

= 5000 cm ( 1 m = 100 cm,

so, 50 m = 5000 cm)

Tile can be fix in wall = area of wall / area of

square tile

= 5000 cm / 100 cm tile can be fix in a wall = 50 cm