Math, asked by abhaymishra092374, 5 hours ago

11. The side of a square tile is 10 cm. How many tiles can be fixed on one side of a wall which is 2.5 m long and 2 m high ? If the tiles are available at 4 per dozen, find the cost of covering the wall of the room with tiles.​

Answers

Answered by jhajhariasanshray
0

 

Answer:

500 tiles need to be used.

Step-by-step explanation:

Given : The side of a square tile is 10cm. One side of a wall which is 2.5m long and 2m high

To find : How many tiles can be fixed on one fixed on one side of a wall?

Solution :

The side of a square tile is 10 cm=0.1 m.

Area of one tile = 0.1*0.1= 0.01 meter square

One side of a wall which is 2.5 m long and 2 m high,

Area of wall = 2.5*2=5.0 meter square .

Number of tiles = Area of wall / Area of the tile

Number of tiles = 5.0/0.01

Number of tiles =500

Therefore,  500 tiles need to be used..

Step-by-step explanation:

Given : The side of a square tile is 10cm. One side of a wall which is 2.5m long and 2m high

To find : How many tiles can be fixed on one fixed on one side of a wall?

Solution :

The side of a square tile is 10 cm=0.1 m.

Area of one tile = 0.1*0.1= 0.01 meter square

One side of a wall which is 2.5 m long and 2 m high,

Area of wall = 2.5*2=5.0 meter square .

Number of tiles = Area of wall / Area of the tile

Number of tiles = 5.0/0.01

Number of tiles =500

Therefore,  500 tiles need to be used.

Answered by devanshu1234321
3

ANSWER:-

  • 500 TILES
  • 166.66 RS

QUESTION:-

. The side of a square tile is 10 cm. How many tiles can be fixed on one side of a wall which is 2.5 m long and 2 m high ? If the tiles are available at 4 per dozen, find the cost of covering the wall of the room with tiles.?

GIVEN:-

  • SIDE OF SQUARE OF 10 CM
  • LENGTH AND BREADTH OF WALL-2.5m AND 2m

EXPLANATION:-

SINCE THE TILE IS SQUARE ,THE AREA WILL BE S x S ( S IS SIDE)

AREA OF TILE=10 x 10=100 CM ==>0.01

WALL IS RECTANGLE SO IT'S AREA IF L x B

AREA OF WALL=2.5 x 2=5 m

so amount of tile required= \frac{area -of -wall}{yarea-of-1-tile}

===>\frac{5}{0.01}

==>500 tiles.

COST:-

IF ONE DOZEN COST-RS 4

SO 12 TILES WILL COST=4 rs

SO USING UNITARY METHOD,

12=4rs

500=\frac{4}{12} *500 rs

==>166.66 RS

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