11. The side of a square tile is 10 cm. How many tiles can be fixed on one side of a wall which is 2.5 m long and 2 m high ? If the tiles are available at 4 per dozen, find the cost of covering the wall of the room with tiles.
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Answer:
500 tiles need to be used.
Step-by-step explanation:
Given : The side of a square tile is 10cm. One side of a wall which is 2.5m long and 2m high
To find : How many tiles can be fixed on one fixed on one side of a wall?
Solution :
The side of a square tile is 10 cm=0.1 m.
Area of one tile = 0.1*0.1= 0.01 meter square
One side of a wall which is 2.5 m long and 2 m high,
Area of wall = 2.5*2=5.0 meter square .
Number of tiles = Area of wall / Area of the tile
Number of tiles = 5.0/0.01
Number of tiles =500
Therefore, 500 tiles need to be used..
Step-by-step explanation:
Given : The side of a square tile is 10cm. One side of a wall which is 2.5m long and 2m high
To find : How many tiles can be fixed on one fixed on one side of a wall?
Solution :
The side of a square tile is 10 cm=0.1 m.
Area of one tile = 0.1*0.1= 0.01 meter square
One side of a wall which is 2.5 m long and 2 m high,
Area of wall = 2.5*2=5.0 meter square .
Number of tiles = Area of wall / Area of the tile
Number of tiles = 5.0/0.01
Number of tiles =500
Therefore, 500 tiles need to be used.
Answered by
3
ANSWER:-
- 500 TILES
- 166.66 RS
QUESTION:-
. The side of a square tile is 10 cm. How many tiles can be fixed on one side of a wall which is 2.5 m long and 2 m high ? If the tiles are available at 4 per dozen, find the cost of covering the wall of the room with tiles.?
GIVEN:-
- SIDE OF SQUARE OF 10 CM
- LENGTH AND BREADTH OF WALL-2.5m AND 2m
EXPLANATION:-
SINCE THE TILE IS SQUARE ,THE AREA WILL BE S x S ( S IS SIDE)
AREA OF TILE=10 x 10=100 CM ==>0.01
WALL IS RECTANGLE SO IT'S AREA IF L x B
AREA OF WALL=2.5 x 2=5 m
so amount of tile required=
===>
==>500 tiles.
COST:-
IF ONE DOZEN COST-RS 4
SO 12 TILES WILL COST=4 rs
SO USING UNITARY METHOD,
12=4rs
500= rs
==>166.66 RS
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