Question

11. The size of a square field is 40 m long. What will be the area of a field. Also find the cost
of weeding of the field at the rate of 2 per square metre.
24​

Answer 1

Given:-

• Side of square field = 40 m

To find:-

• Area of the field.
• Cost of weeding the field at the rate of 2 per square metre.

Solution:-

We know,

Area of Square = (side)²

= $\sf{Area\: of \:field = (40)^2}$

= $\sf{Area\:of\:field = 40\times40}$

= $\sf{Area\:of\:field = 1600\:m^2}$

Now,

Cost of weeding 1 m² = Rs.2

= $\sf{Cost\:of\:weeding\:1600\:m^2 = 2\times1600}$

= $\sf{Cost\:of\:weeding\:1600\:m^2 = 3200}$

Therefore cost of weeding the field at rate of Rs.2 per metre square is Rs.3200.

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Formulas Used:-

• Area of Square = (side)² sq.units.

Extra Formulas:-

• Perimeter of square = (4×side) units
• Area of rectangle = (Length×Breadth) sq.units
• Perimeter of rectangle = 2(Length + Breadth) units.

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Answer 2

$\large{ \sf \underline{ \red{\: Question : - }}}$

The size of a square field is 40 m long. What will be the area of a field. Also find the cost

of weeding of the field at the rate of 2 per square metre.

24

$\large{ \sf \underline{ \red{To\:Find : - }}}$

Area of square = ?

$\large{ \sf \underline{ \red{Solution: - }}}$

➜Here (a) = side

• Area of Square = (a)²

$\bf \sf{Area\: of \:field = (40)^2} \\ </p><p></p><p> </p><p>\bf \sf{Area\:of\:field = 40\times40} \\ </p><p></p><p>\bf \sf{Area\:of\:field = 1600\:m^2}</p><p></p><p>$

$\large{ \sf \underline{ \blue{after \: that : - }}}$

Cost of weeding 1 m² = Rs.2

$\bf \sf{Cost\:of\:weeding\:1600\:m^2 = 2\times1600} \\ </p><p> </p><p>\bf \sf{Cost\:of\:weeding\:1600\:m^2 = 3200}$

$\large{ \sf \underline{ \purple{\: \: ◕So \: cost \: of \: weeding \: the \: field \: is \: Rs.3200.◕: }}}$