11. The speed-time graph for a car is shown is Fig. 22
(a) Find how far does the car travel in the first 4
seconds. Shade the area on the graph that
represents the distance travelled by the car
during the period. (b) Which part of the graph
represents uniform motion of the car?
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Explanation:
The total number of divisions on horizontal axis for 2 s is 5.
The total number of divisions on vertical axis for 2 m/s is 3.
The total displacement of the car during these two seconds will be given as the area under all these squares.
The area under the (3×5) squares is given as:
A
15
=2×2 = 4
So, the area under one small square is :
A
1
=
15
4
Now, the area under the graph for 4 sec is:
the number of squares under the graph is :
n=57 small squares + 6 half small squares
So, total number of squares =60.
So, the distance traveled by the car is the area under the curve.
S=60×
15
4
S=16 m
(b)
The car moves under the uniform motion after the instant t=6 s because after this instant, the speed of the car becomes constant.
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