Question

11. The sum of 3rd and 7th terms of an A.P. is 14 and the sum of 5th and 9th terms s 34. Find
the first term and common difference of the A.P.​

Answer 1

Answer:

A=-9 & D=5

Step-by-step explanation:

let the 3, 7, 5 , 9 terms of an AP be

T3 ,T7, T5,T9 respectively

by using the formula

tn=a+(n-1)d

Therefore ,

t3=a+2d

t5=a+4d

t7=a+6d

T9=a+8d

according to given conditions

t3+t7=14 &

t5+T9=34

Therefore ,

2a+8d=14...............1

2a+12d=34..............2

Now , Subtracting 1 from 2

we get 4d =20

Thus , D=5

substituting D's value in 1

2a+32 = 14

thus 2a=-18

and A=-9

Answer 2

Answer:

ur from...............tamil ahh