11. The sum of 7 consecutive numbers is 1617 then the number of prime numbers in it.
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Let the numbers be n, n-1, n+1, n-2, n+2, n-3,n+3. Sum = 7n
Hence, 7n = 1617
Thus, n = 231
The numbers are = 228, 229, 230, 231, 232, 233, 234
Out of these, 229 and 233 are prime.
Hence, 7n = 1617
Thus, n = 231
The numbers are = 228, 229, 230, 231, 232, 233, 234
Out of these, 229 and 233 are prime.
Answered by
2
Answer:
Let the numbers be n, n-1, n+1, n-2, n+2, n-3,n+3. Sum = 7n
Hence, 7n = 1617
Thus, n = 231
The numbers are = 228, 229, 230, 231, 232, 233, 234
Out of these, 229 and 233 are prime.
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