Question

11.The sum of a number and its reciprocal is 10/3, and then write the quadratic

equation to find the number.​

Answer 1

Step-by-step explanation:

let the number be x reciprocal =1/x

x+1/x=10

(x²+1)/x=10/3

x²+1=10/3x

x²-10/3 x+1 =0

root for quadratic equation =[-b+/-(b²-4ac)^1/2]/2a

a,b,c are constants

pattern = ax²+bx+c=0

a=1 b=-10/3 c=1

[-(-10/3)+(100/9-4)^1/2]/2

[10/3+(64/9)^1/2]/2

[10/3+8/3]/2

[18/3]/2

9/3 or 3

note:a^1/2=root under a

hope this helps you