11. The sum of digits of a two digit number is 9.
The digits are reversed when 9 is added to the
number. Find the number.
Answers
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Answer:
45
Step-by-step explanation:
Answer would be 45.
If you add 9 to it, you get 54, in which digits of 45 are reversed.
OK. Now the question is how to find it.
Let say tn be the first two-digit number.
Its value can be written as 10t+n , and we kno w t+n=9
Adding 9 to tn would make it reversed and thus its value would be 10n+t
Now we have
t+n=9 and
10t+n+9=10n+t
⇒9t+9=9n
⇒t+1=n⇒t−n=−1
Therefore from t+n=9
We will have, 2t=8⇒t=4
and t+n=9 gives n=5
So the required number tn=10t+n=45 .
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