Question

11. The sum of first n terms of an AP is given
by Sn=4n2+ n. Find that AP:​

Answer 1

Answer:

AP = 5 ,13 ,21 , 29 , _ _ _ _ _ _

Step-by-step explanation:

Sn = 4n2 + n

S1 = 4(1) + 1 = 5

S2 = 4(4) + 2 =18

S2 = a1 + a2 ; S1 = a1 = 5,

=>18 = 5 + a2

=> 13 = a2

d = a2 - a1

=>d = 13 - 5 = 8

a3 = a2 + d = 13 + 8 = 21

HOPE U FIND IT HELPFULL!!!