Question

11. The sum of the digits of a two-digit number is 11.
The digit at one's place is 2 more than twice the
digit at ten's place. Find the number. what is answer. 38 or 15​

Answer 1

Answer:

your answer is 38

Step-by-step explanation:

lets us take number as 10x+y

x+y=11 ...(1)

The new number after reversing the digits is equal to the original number.

∴(y−5)∗10+x+5=10x+y

⇒10y−50+x+5=10x+y

⇒10y−45+x=10x+y

⇒9y−9x=45

⇒y−x=5 ...(2)

eq (1)+eq (2)

2y=16

y=8

So, x=3

Hence, the number is 38.

Answer 2

Step-by-step explanation:

Let one's place digit be ' y ' and

Let ten's place digit be ' x '

by the given condition,

x + y = 11 -----(1)

and

x = 2y + 2

x - 2y = 2 -----(2)

Subtracting eqn (2) from eqn (1)

x + y = 11

-

x - 2y = 2

_______

3y = 9

y = 3

from eqn (1)

we get,

x + 3 = 11

x = 11 - 3

x = 8