Question

11. The sum of the digits of a two-digit number is 12. If the new number formed by reversing
the digits is greater than the original number by 54, find the original number. Check your
solution.​

Answer 1

let the 2 digit no. be 10x + y

A/Q,

=> x + y = 12.............eq.1

and

=> 10y + x = 10x + y + 54

=> 9y = 9x + 54

=> y = x + 6..........eq.2

putting eq.2 in eq.1

=> x + x + 6 = 12

=> 2x = 6

=> x = 3

then from eq.2

=> y = 3 + 6 = 9

therefore the original no. is 39